Answer:
Option A
Explanation:
Given weight of solute 98 g, molar mass of solute 98 g mol-1 weight of solute =2g
Molality= weight of $H_{2}SO_{4}$/ molecular weight of $H_{2}SO_{4}$
$\times$ 1000/ weight of water
=$\frac{98}{98} \times \frac{1000}{2}=500 m$